When flipping 100 coins The total number of ways to find two coins with heads up is?

When flipping 100 coins The total number of ways to find two coins with heads up is?

Explanation : Make 2 piles and say pile one has ‘h’ no. of heads and ‘t’ no. of tails while the other pile will have ’10-h’ heads and ’90-t’ tails. Now we can flip coins of one pile,so lets flip coins of any pile(say 2nd pile) then no.

How do you find the ratio of heads to tails?

As each coin is flipped until a HEADS is obtained, the total number of HEADS will be n . The expected number of TAILS for a coin would be 2−1=1 2 − 1 = 1 . The ratio of HEADS and TAILS would be 1:1 . This can also be seen intuitively.

How do you equally divide pairs of heads and tails from a random lot of coin kept in a dark room?

In the group of 10, if there are x number of heads there are 10 – x number of heads in the other group and 10 – x number of tails in the same group. So flipping all the ten would equal the number of heads. This works for every pair of a heads and b tails. Divide the coins into groups of ‘a’ & ‘b’.

How many ways can 50 heads be achieved by tossing 100 coins?

It is assumed that a fair coin is being tossed, i.e., getting a head and getting a tail have equal probability of 0.5. If you toss the coin 100 times, number of possible outcomes = (2^100). Now, for getting 50 heads in 100 tosses, number of possible outcomes = (100C50). So, the probability = (100C50) / (2^100).

What is the probability of getting exactly 3 heads?

0.125
Answer: If you flip a coin 3 times the probability of getting 3 heads is 0.125. When you flip a coin 3 times, then all the possibe 8 outcomes are HHH, THH, HTH, HHT, TTH, THT, HTT, TTT.

What is the probability of getting 1 head and 2 tails?

3/8
Only one of the eight outcomes represents the event of 0 heads, so its probability is 1/8. Three of the eight outcomes represent the event of 1 head (and 2 tails): HTT, THT, and TTH. This event therefore has a probability of 3/8. Solution: (cont.)

When flipping 5 coins how many sequences of heads and tails have exactly 2 heads?

There are (52)=10 sequences of five coin tosses with exactly two heads, of which four have consecutive heads (since the first of these consecutive heads must appear in one of the first four positions). Hence, there are 10−4=6 sequences of five coin tosses with exactly two heads in which no two heads are consecutive.

What is the minimum number of weighings needed to identify the stack with the fake coins?

What is the minimum number of weighings needed to identify which stack contains the fake coins? Explain. Author’s hint: The answer is that one weighing is enough.